It seems like you are trying to understand how objects work in JavaScript. In your example, you have two objects "obj" and "obj2". The first object "obj" has a name property and a getName function that returns the name property using "this" keyword. The second object "obj2" has roll, desig, and name properties along with a "_proto_" property that points to "obj". Finally, you log the typeof of the result of obj.getName() and obj2.getName(). The "this" keyword refers to the object that it belongs to. In this case, it refers to the object that calls the function. So when obj.getName() is called, it returns the name property of obj which is "John". Similarly, when obj2.getName() is called, it returns the name property of obj2 which is "Jane". The typeof operator returns a string indicating the type of the operand. In this case, since both obj.getName() and obj2.getName() return strings, typeof will return "string". I hope this helps! Let me know if you have any other questions.

The code above outputs "Type string" and "Peter" in the console. The first part of the code initializes an object obj with a name property and a getName method which returns the name property. When getName is called on obj, it returns the string "John" which has a type of string. The second part of the code initializes another object obj2 with additional properties roll and desig along with a name property. It also has a _proto_ property which references the obj object. This sets up prototype inheritance between the two objects so that obj2 inherits properties and methods from obj. When obj2.getName() is called, the getName method is looked up on obj2. Since it doesn't have its own getName method, it checks its prototype, which is obj, and finds getName there. It then calls the getName method on obj with this set to obj2, which returns the name property of obj2 ("Peter").