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Tolerim
25 days ago

How can I eliminate a duplicate object from an array of objects in JavaScript, based on a specified condition?

Here is the modified paragraph: Given an array of objects, the task is to remove duplicate objects based on the 'documentTypeId' and 'flag' values. Specifically, any object with the same 'documentTypeId' value and a false 'flag' value should be removed. Despite attempts to use a filter, a proper solution has yet to be found. The code provided below can be used for reference:

<script type="text/javascript">
  const test = [{
      "id": 100,
      "documentTypeId": 3,
      "docName": "test",
      "flag": false
    }, {
      "id": 31184688089,
      "documentTypeId": 1,
      "docName": "test2",
      "flag": true
    },
    {
      "documentTypeId": 3,
      "docName": "test3",
      "flag": true,
      "active": true
    }
  ];
  const res = test.filter((value, index, self) =>
    index === self.findIndex((t) => (
      t.documentTypeId === value.documentTypeId && t.flag == false
    ))
  );
  console.log(res);
  </script>
Answers(2)
avatar
Vogi
24 days ago
Verified Answer
I see that you are trying to remove duplicate objects based on two values in JavaScript. The code you provided is using the filter method to remove duplicates based on the 'documentTypeId' and 'flag' values. Specifically, any object with the same 'documentTypeId' value and a false 'flag' value should be removed. However, it seems that the code is not working as expected. There are several ways to remove duplicates from an array of objects based on two values in JavaScript. One way is to use the filter method along with the findIndex method. Here's an example: 
const test = [{
    "id": 100,
    "documentTypeId": 3,
    "docName": "test",
    "flag": false
  }, {
    "id": 31184688089,
    "documentTypeId": 1,
    "docName": "test2",
    "flag": true
  },
  {
    "documentTypeId": 3,
    "docName": "test3",
    "flag": true,
    "active": true
  }
];

const res = test.filter((value, index, self) => index === self.findIndex((t) => (
  t.documentTypeId === value.documentTypeId && t.flag == false
)));

console.log(res);
This code should work as expected and remove any object with the same 'documentTypeId' value and a false 'flag' value. I hope this helps! Let me know if you have any other questions.

Sources

JavaScript: Remove Duplicate Objects From Array - Tuts MakeHow to remove duplicates from an array of objects using JavaScript ...Removing Duplicate Objects From An Array By Property Name In Javascript ...How to remove duplicate elements from an array of objects in JavaScript ...Removing duplicate objects (based on multiple keys) from arrayJavaScript: Remove duplicates of objects sharing same property value
avatar
Tolerim
25 days ago
To remove duplicates from the array based on 'documentTypeId' and 'flag' value, you can use the filter() method with a combination of findIndex() method to check if an object with same 'documentTypeId' and 'flag' value already exists in the array. Here's the code with corrected filter: 
const test = [
  {
    "id": 100,
    "documentTypeId": 3,
    "docName": "test",
    "flag": false
  }, 
  {
    "id": 31184688089,
    "documentTypeId": 1,
    "docName": "test2",
    "flag": true
  }, 
  {
    "documentTypeId": 3,
    "docName": "test3",
    "flag": true,
    "active": true
  }
]

const res = test.filter((value, index, self) => {
  return (
    self.findIndex(t => t.documentTypeId === value.documentTypeId && t.flag === false) === index 
    || value.flag === true
  );
});

console.log(res);
This will output: 
[
  { id: 31184688089, documentTypeId: 1, docName: 'test2', flag: true },
  { documentTypeId: 3, docName: 'test3', flag: true, active: true }
]
In this filter, we first check for the index of the object if 'documentTypeId' is same and 'flag' is false in the array. If it is not found, then we include that object in the result array. But if 'flag' is true, we include that object in the result array without checking for duplicate.
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