Technologies:
Tolerim
a day ago
How can I include or omit text within parentheses using a regular expression?
The following code can be used to allow both "text1 text2" and "text2" as correct answers:
var getalt = document.getElementById('altmean');
var altmean = getalt.innerHTML.replace(/(\([^)]*\))/g, '').replace(/[^\w,éôëçñï]/g,' ');
altmean += ", ";
altmean += correctAnswer;
var array = altmean.split(",").map(function(item) {
return item.trim();
});
var finalArray = [];
for (var i = 0; i < array.length; i++) {
var subArray = array[i].split(" ");
var index = subArray.indexOf("(" + subArray.slice(-1)[0] + ")");
if (index > -1) {
var newArr = subArray.slice(0, index+1);
finalArray.push(newArr.join(" "));
}
finalArray.push(subArray[subArray.length-1]);
}
if (!finalArray.includes(correctAnswer)) {
finalArray.push(correctAnswer);
}
for ( var i = 0; i < finalArray.length; i++ ) {
finalArray[i] = "" + finalArray[i].toUpperCase() + "";
finalArray[i] = "" + finalArray[i].replace(/[/\W, " "]/g,' ');; + "";
finalArray[i] = "" + finalArray[i].replace(/\s/g, ''); + "";
}
//Modify answer output
if ((finalArray.indexOf(typedUpper) > -1) && (!(typedUpper == "" ))) {
var c = ""+typedAnsDis+"";
var d = document.getElementById('typeans');
d.innerHTML = c;
} else {
if(typedAnsDis == "") {
var g = "{{Meaning}}"+typedAnsDis+"";
var h = document.getElementById('typeans');
h.innerHTML = g;
const div = document.getElementById('empty');
div.innerHTML = div.textContent.split('').filter(char => /^[A-Za-z\s\.,;!?"'-~-éū]+$/.test(char) && !/[^\x00-\x7F]/.test(char)).join('');
} else {
var e = ""+typedAnsDis+"";
var f = document.getElementById('typeans');
f.innerHTML = e;
}
}
This code splits the possible correct answers into arrays of words, and checks whether the last word of each array is enclosed in parentheses. If it is, the entire array is considered as a correct answer. Otherwise, only the last word is considered as a correct answer. The resulting array is then used to modify the answer output.Answers(1)
Tolerim
a day ago
Verified Answer
To count both "text1 text2" and "text2" as correct answers, you can modify the regular expression in the correctParse variable to include both options. Here's an example of what that regex might look like:
var correctParse = str2.replace(/(([^\)]*\))?\s*(\w+))/g,'$2$3').replace(/[^\w,éôëçñï]/g,'');
In this new regex, we are capturing both "text1)" and "text2" as separate groups, and then joining them together in the replacement string with no space in between ($2$3).
Note that this may not be the most elegant solution depending on your specific use case, so you may want to modify it further to suit your needs.