Technologies:
Tolerim
20 days ago
What is the correct way to substitute elements using the node-html-parser library?
map((body) => {
let dom = parse(body.toString());
dom.querySelectorAll('a').forEach((link) => {
dom.exchangeChild(link, parse(`<span>lalala</span>`));
});
return dom;
})
Answers(2)
Vogi
19 days ago
Verified Answer
The exchangeChild() method is used to replace a child node of an element with another node. The method returns the replaced node. The reason why it may not be working as intended could be due to a number of reasons such as:
- The element you are trying to replace does not exist.
- The element you are trying to replace is not a child of the parent element.
- The new node you are trying to insert is not a valid node type.
- The new node you are trying to insert is already a child of the parent element.
You can try using the replaceChild() method instead which replaces a child node with another node in the same position in the child list. Here's an example:
let dom = parse(body.toString());
dom.querySelectorAll('a').forEach((link) => {
let span = parse(`<span>lalala</span>`);
link.parentNode.replaceChild(span, link);
});
I hope this helps! Let me know if you have any other questions.
Sources
Bot commands and events not working/responding *FIX* (Discord ... - YouTubeTHIS IS WHY YOUR ROBLOX EXPLOIT IS NOT WORKING - YouTubeFunction Keys Not Working in Windows 10? Here's What to Do - MUOTolerim
20 days ago
It looks like the code is using the exchangeChild() method to replace each element with a new element containing the text "lalala". However, it's possible that this method is not working as expected because it requires both the old and new child elements to be direct children of the same parent element.
One solution could be to create a new element with the desired text, and then replace the entire element with this new element using the replaceWith() method instead. Here's an example:
map((body) => {
let dom = parse(body.toString());
dom.querySelectorAll('a').forEach((link) => {
let span = parse(`<span>lalala</span>`);
link.replaceWith(span);
});
return dom;
})